Lebesgue measure of a bounded set

Question

This seems trivial but how would you prove that an open and bounded set, G, has finite lebesgue measure.

It's contained in a large enough hypercube. – Daniel Fischer Nov 20 '13 at 15:36 — Daniel Fischer, Nov 20 '13 at 15:36

score 1 · Answer 1 · answered Nov 20 '13 at 15:38

1

Let Q be a hypercube large enough that your set A fits nicely inside Q. Then $\mu(A) \leq \mu (Q)$.

answered Nov 20 '13 at 15:38

Peter Halburt

1 Answers1