6x-13+4(-3)x=9+2x
I'm like, really dumb, I can't tell if if the 4(-3) bit is a multiplication
6x-13+4(-3)x=9+2x
I'm like, really dumb, I can't tell if if the 4(-3) bit is a multiplication
Yes, it is multiplication that's implied. It's called "juxtaposition", where factors in a product abut each other. Unless otherwise specified, we take the operation to be multiplication. $$a(b)c = abc = a\times b\times c$$
Yes, it is a multiplication. In mathematical notation, we often just leave out multiplication signs when they are implied.
$6x-13+4(-3)x=9+2x$
is the same as the equation $6*x-13+4*(-3)*x=9+2*x$
which is the same as $(6*x)-13+(4*(-3)*x)=9+(2*x)$
which is the same as $(6*x)-13+((-12)*x)=9+(2*x)$
which is the same as $(6*x)-13-(12*x)=9+(2*x)$
What happens is something similar to what happens when you add an x into the equation. Just like $6x$ is the same as $6*x$ the same happens with parenthesis. so $4(3)$ is the same as $4*3$