$$\mathbf{A}=\mathbf{B}\mathbf{T}= \begin{pmatrix} 3& 3 & 0 \\ 4 & 0 & 1 \\ 0 & 4 & 5 \\ \end{pmatrix} $$
Every Nash equilibria of this game is symmetric, that is, $x = y$, where $xT$ is one of $(0, 0, 1), (\frac{1}{2},\frac{1}{4},\frac{1}{4}), \text{or} (\frac{3}{4},\frac{1}{4},0)$. Follow the LH paths starting at $(0, 0)$for all missing labels, and explain what you observe.
My question is: Why it is enough to consider the missing labels 1, 2 and 3. please can anyone help me out?
