
What I did:
1)
$\angle DAB = 180-(50+75+x)$ $= 180-(125+x)$ $= 55-x$
But, that resulted in:
$50+75+55-x+x=180 \implies 180=180$ (x value not found)
2)
$\angle CPB = 180-(75+x) = 105-x$
$105-x+75+x=180 \implies 180=180$ (x value not found)
This question came in the competition that I gave today and I am in 9th class and was not able to solve this question.
The options there were:
(A) $60^\circ$
(B) $50^\circ$
(C) $55^\circ$
(D) $70^\circ$
(E) None of these
Now, please let me know how to solve this problem. PLEASE DO EXPLAIN! I want to know whether I scored full $\frac{40}{40}$ or ${39}{40}$.
I answered '(B) $50^\circ$' as I thought that the answer has to be lower than at least $55^\circ$ and $50^\circ$ was the only option of this.