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Consider the curve $y=x^{2/3}$:

a. Sketch the curve between $x=-1$ and $x=8$. ( I sketched it already)

b. Explain why the formula $$ \int_{-1}^{8}\,\sqrt{1+ \left({\rm d}y \over {\rm d}x\right)^{2}\,}\,\,{\rm d}x $$ cannot be used to find arc length of the curve sketched. because $\displaystyle{{{\rm d}y \over {\rm d}x} = {2 \over 3x^{1/3}}}$. Therefore, is undefined at $x=0$.

c. Find the arc length of the curve. Solve for $x$, $x=y^{3/2}$, and use the arc length with $y$ bounds which are from $1$ to $4$.

Felix Marin
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Evo
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1 Answers1

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Derivative $x'=\frac{3}{2}y^{0.5}$, square it to get $\frac{9y}{4}$. Put in arc length formula to get $(1+\frac{9y}{4})^{0.5}$. Now integrate to obtain $\frac{4}{9}*\frac{2}{3}(1+\frac{9y}{4})^{1.5}$ running from 1 till 4. Can you finish it now?

imranfat
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