Finding unit vector perpendicular to U

Question

given u=[0,4,3]T a unit vector that is prependicular to u is

How can I find the normal?

I am new to these stuff.

Thanks

In tridimensional space there are a plane of perpendicular vectors to $u$. — Sigur, Dec 06 '13 at 17:33
Just find "by inspection" any vector which has a zero scalar product with your vector. Then divide by its length to get a unit vector. — Old John, Dec 06 '13 at 17:39
http://math.stackexchange.com/questions/133177/finding-a-unit-vector-perpendicular-to-another-vector
there is complete answer ,please see it — dato datuashvili, Dec 06 '13 at 17:55
so if i want to find normal to <-10,-2,-8> ---> -10x-2b-8c=0 what do I do after? — user107895, Dec 06 '13 at 20:00

score 0 · Answer 1 · edited Apr 13 '17 at 12:19

0

ok in your case vector is simple $u=[0,4,3]$,for some vector s,we say that $s$ is perpendicular to $u$,if $s*u=0$,so let us suppose that

$s=(s_1,s_2,s_3)$ ,so we have

$S_1*0+s_2*4+s_3*3=0$,

after that follow this rule

edited Apr 13 '17 at 12:19

Community

answered Dec 06 '13 at 17:58

dato datuashvili

so if i want to find normal to <-10,-2,-8> -10x-2b-8c=0 what do I do after? – user107895 Dec 06 '13 at 19:58
choose any values of $x$,$b$ and $c$ which satisfy these solution,but to gain unit vector,divide this vector by its length – dato datuashvili Dec 06 '13 at 20:07

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