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If $$\sqrt[n]{{abc}} = 1,$$ Prove that $$\frac{\sqrt[n]a}{\sqrt[n]{ab}+\sqrt[n]a+1}+\frac{\sqrt[n]b}{\sqrt[n]{bc}+\sqrt[n]b+1}+\frac{\sqrt[n]c}{\sqrt[n]{ac}+\sqrt[n]c+1}=1.$$

Bart Michels
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1 Answers1

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Let $x = \sqrt[n]a, y = \sqrt[n]b, z = \sqrt[n]c$. Then you have $xyz = 1$ and $$\frac{x}{xy+x+1}+\frac{y}{yz+y+1}+\frac{z}{zx+z+1} = \frac{x}{xy+x+1}+\frac{xy}{1+xy+x}+\frac{1}{x+1+xy}$$

where we multiplied the second term's numerator and denominator by $x$ and the third term's by $xy$.

Macavity
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