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I want to describe the following scenario mathematically. I think I have it right... Just wanna check!

Lets say we take a reading A. We then take a number of readings (R) (n readings). We then calculate the difference between each reading & A. We then average out these differences & this becomes our result (R).

So, here's what I have: $$ R = \sum\limits_{i=1}^n \overline{(A-R_1 ... A-R_n)} $$

user114381
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1 Answers1

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The average difference is $\frac{1}{n} \sum_{i=1}^n (A-R_n)$ which is equal to $A-\frac{1}{n}\sum_{i=1}^n R_n$ which is equivalent to $A-\overline{R}$, where for clarity you might want to define $\overline{R}=\frac{1}{n}\sum_{i=1}^n R_n$.

Is that the answer you're looking for?

Jeff Snider
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