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At a parking garage, automobiles enter at a rate of $1$ car every $2$ minutes. I need to find the probability that the number of automobiles entering the garage during any $2$ minute period exceeds $3$.

I know $\Pr(x \gt 3)= 1-\Pr(x\le 3)$.

So, $1-\left(e^{-1} + e^{-1} + \frac{1}{2} e^{-1} + \frac{1}{6} e^{-1}\right) \dots$.

Garrett
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pgrado
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1 Answers1

-1

About the statement

The Probability that the event exceeds 3 is not the same that the event happen at least 3 times.

The Probability that the event exceeds 3 is the same as the probability that the event happen at least 4 times.

Then we can perform

P(x>3) = 1 - P(x<=3)

Best Regards