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a pool 20 ft by 30 ft is going to have a deck x feet wide added all the way around the pool write an expression in simplified form for the area of the deck. I have tried doing this but have failed please help

crisrex
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2 Answers2

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You are on the correct path cris.

The pool is still a rectangle, even with the new deck. Thus you are almost correct.

Each side will have $x$ feet added to it.

Thus it will be $(20+2x)(30+2x) = 4x^2+100x+600$

Try finding the answer to this:

If there is only 120 Feet of bamboo for the new deck,what is the largest the new area (pool + deck) can be.

yiyi
  • 7,352
  • thank you really helped it's 2x because there are 4 side right so 2+2 +4 so basically 2x is acounting for two sides right? – crisrex Dec 13 '13 at 06:34
  • There are only four side to a rectangle. Did you draw the rectangle in a rectangle? It always helps to draw a picture when you want to do mathematical problems. – yiyi Dec 13 '13 at 06:36
  • I did so is 4x squared + 100x + 600 right what is the point of drawing a rectangle wouldn't it be easier to just foil straight away? – crisrex Dec 13 '13 at 06:38
  • Cris, it so you can understand what is going on. Can you see where the deck would be on the outside of the pool. – yiyi Dec 13 '13 at 06:40
  • yeah so its like a picture frame the frame is the x and the picture is the length and width – crisrex Dec 13 '13 at 06:44
  • You also need to subtract the area of the pool. – Steve ODonnell Dec 13 '13 at 07:00
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Area of the deck=$20x+20x+30x+30x=100x$

Vikram
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