Let $f: \mathbb R \rightarrow \mathbb R$ be a periodic function, which means that there is some positive $p$ such that $f(x)=f(x+p)$ for all $x$. Is it the case that, if there is no minimum such $p$, then the $f$ must be a constant function?
Asked
Active
Viewed 512 times
2 Answers
5
No: Let $f$ be the function which is $1$ on all the rationals, and $0$ on all the irrationals. Then every positive rational number is a period of $f$.
-
-
1@voldemort: Let $f(0)=c$. For any $a$, there are $x$ arbitrarily close to $a$ such that $f(x)=c$. But if $f$ is continuous at $a$, we have $f(a)=\lim_{x\to a}f(x)=c$. – André Nicolas Jan 25 '14 at 08:07
1
I found a kind of explanation on Math-World,"The constant function f(x)=0 is periodic with any period R for all nonzero real numbers R, so there is no concept analogous to the least period for constant functions."
EnglishPatient
- 119