We want to approximate a function $f$ with a second-degree interpolating polynomial in the interval $[-1,1]$. I need to pick three interpolation points such that the interpolation polynomial $p$ has the best possible approximation. I need to argue that it's best to pick the interpolation points symmetrically. Then I am given a hint which is; the solution to the equation $\frac{2}{3\sqrt{3}}\tau^3 = 1 - \tau^2 $ is $\tau = \frac{1}{2}\sqrt{3}$.
The error using second degree interpolation at the interpolation points $x_0, x_1, x_2$ at the point x is given by $$(x - x_0)(x - x_1)(x - x_2)\frac{f^{3}(\xi)}{6}$$ for some $\xi \in [-1,1]$.
We could probably argue that if we did not pick the interpolation points symmetrically, then the term $(x - x_0)(x - x_1)(x - x_2)$ would start behaving very wildly. I do not really see how the given hint applies here.