write an equation of a line parallel e given line through the given point
$y=\frac{1}{2}(x-2)$ and point $(3,6)$ I don't know how to do this I don't know what to try I feel hopeless
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Your given line $y=\frac{1}{2}x-2$ has slope $\frac{1}{2}$. Any line parallel to this has slope $\frac{1}{2}$, and therefore equation of shape $y=\frac{1}{2}x+b$. To choose $b$ so the line goes through $(3,6)$, substitute. We get $6=\frac{1}{2}(3)+b$, so $b=\frac{9}{2}$. If your original line was $y=\frac{1}{2}(x-2)$, the slope is still $\frac{1}{2}$, so the solution and answer are the same. – André Nicolas Jan 30 '14 at 05:19
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I don't get it , so there is no answer – aaly b Jan 30 '14 at 05:27
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Sure there is an answer, and I gave it. It is $y=\frac{1}{2}x+b$, where $b=\frac{9}{2}$. – André Nicolas Jan 30 '14 at 05:34
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The equation of a line passing through a point $(a,b)$ and has a slope $m$ is $$y-b=m(x-a)$$ and so simply you have $$y-6=\frac{1}{2}(x-3)\\ y=\frac{1}{2}x-\frac{3}{2}+6\\ y=\frac{1}{2}x-\frac{9}{2}$$
Semsem
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So you accept my this answer, as always if you face any problem just let me know – Semsem Jan 30 '14 at 05:35
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you can use this form first put $m=\frac{1}{2}$ then use the point to get $b$. If you need to simplify the above result just move -6 to the opposite side – Semsem Jan 30 '14 at 05:41
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