$3^{x+4} * 5^{x+7} * 15^{2x-1}$
I tried it in this way:
$3^{x+4}*5^{x+1}*(3*5)^{2x-1}$
Then:
$3^{x+4}*5^{x+1}*3^{2x-1}*5^{2x-1}$
And what about next?
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2A start: $3^{x+4}\cdot 3^{2x-1}=3^{(x+4)+(2x-1)}=3^{3x+3}$. – André Nicolas Feb 03 '14 at 19:33
1 Answers
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Write as $3^{x+4}*3^{2x-1}*5^{x+1}*5^{2x-1}$ (using the commutative property of multiplication) and then use the rule that $b^n*b^m = b^{n+m}$.
John Habert
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