Use equational proofs to solve the problem:
$ \vdash A \lor B \equiv A \lor \lnot B \equiv A $
These are the Axioms and the theorems :



Use equational proofs to solve the problem:
$ \vdash A \lor B \equiv A \lor \lnot B \equiv A $
These are the Axioms and the theorems :



Start with the following instance of (2.4.12):
$$\vdash \lnot B \lor A \equiv B \lor A \equiv A.$$
By the symmetry of equivalence (2) we obtain:
$$\vdash B \lor A \equiv \lnot B \lor A \equiv A.$$
By the symmetry of disjunction (6) we obtain:
$$\vdash A \lor B \equiv A \lor \lnot B \equiv A.$$
I'm not familiar with the system; I apologize if this is not the sort of derivation you're looking for.