I'm currently working on some statistics homework, and as you might guess from the title, I got the wrong result, and the reason why I'm writing it here is because I don't have a clue why it's wrong.
The question is as follows:
A student is driving from city A to B. On route to B there's 2 intersections where she will randomly choose which one to pass through.
1. At the first intersection she can choose between Bridge A or B in the proportion 3:1 (Meaning bridge A is chosen with probability 3/4).
At bridge A there's a 0.5 probability of being delayed by 0 mins. and a 0.5 probability of being delayed by 10mins.
At bridge B there's a 0.4 probability of being delayed by 5mins. and a 0.6 probability of being delayed by 7mins.
2. At the second intersection she can choose between road A or B in the proportion 2:1.
At road A there's a 0.5 probability of being delayed by 1min. and a 0.5 probability of being delayed by 2 mins.
At road B there's a 0.1 probability of being delayed by 3mins. and a 0.9 probability of being delayed by 9mins.
Out from this answer the following:
- Let X be a stochastic variable which shows the student's total delay in minutes between city A to B. Calculate the following: $S_x$, $E(X)$, $Var(X)$ and $\sigma_X$
Let's just take the calculation for $S_X$ since I find that one to be the hardest.
Since X is stochastic I can find that it has the following values: 1, 2, 3, 6, 7, 8, 8, 9, 10, 11, 12, 13, 14, 16, 19
In order to calculate $S_x$ I have to calculate the expected value which I did as:
E(X)=$\frac{(1+2+3+6+7+8+8+9+10+11+12+13+14+16+19)}{15} = 9.2667$
Then I believe I calculate $S_X$ the following way:
$S_X$ = $\sqrt(\frac{E(X)}{N})$ = 4.8634
Unless I'm using the wrong method (which I most likely am), then there's something missing in my book because what my teacher calls $S_X$ "Support". Which I can find nothing about, I also tried to look up standard deviation, which also turned out to be wrong.

