Let $C$ be a positive definite matrix, $D$ be a diagonal matrix with all elements being positive and $A=C+D$. By Woodbury matrix identity, we have $A^{-1}=C^{-1}-C^{-1}(D^{-1}+C^{-1})^{-1}C^{-1}$ or $A^{-1}=D^{-1}-D^{-1}(C^{-1}+D^{-1})^{-1}D^{-1}$. However, we have no idea about $(D^{-1}+C^{-1})^{-1}$. My question is as followings:
- Is there is closed form of $A^{-1}$ in terms of $C$(or $C^{-1}$) and $D$(or $D^{-1}$)?
- If no, is there a explicit relation between $A^{-1}$ and $C$ and $D$ through their eigenvalues and eigenvectors?
Thanks!