give x in the form A $ \sqrt B$ + C
$(\sqrt 3x) = 3$
can someone show me how to solve this please?
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Since $3 = \sqrt{3} \sqrt{3}$, divide both sides by $\sqrt{3}$ to get $x=\sqrt{3}$. Is this OK or do you need more ? – Claude Leibovici Mar 07 '14 at 11:53
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I understand now thanks for explaining it to me. – user133745 Mar 07 '14 at 12:08
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You are welcome. – Claude Leibovici Mar 07 '14 at 12:09
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(√3x) = 3
=> 3x^2 = 9 {Squaring both sides}
=> x^2 = 9/3
=> x^2 = 3
=> x = +√3 or -√3 {as square of a positive or negative number will be a positive no. so using the converse of this fact ie square root of a number may be positive or may be negative but not both.}
Now, the Answer will be x = √3 as this satisfies the equation (√3x) = 3 when x value is substituted as √3.
Kailas
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