Find the value of $x$ in:
$5.25 = -\log_{10} (x)$
What should I do with a negative log?
Should i do $5.25= \frac{1}{\log_{10}(x)}$ ?
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2$-\log x=\log\dfrac1x\neq\dfrac1{\log x}$ – Lucian Mar 09 '14 at 09:36
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1-5.25=log10(x). Then x=10^(-5.25). – measure2012 Mar 09 '14 at 09:38
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so is $5.25=log{1\over {x}}$ equal to $-5.25=log(x)$ ? – Helena Mar 09 '14 at 09:46
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Logarithms to the base $a$ mean: $y = a^x \iff x = \log_a(y)$
Therefore, $5.25 = -\log_{10}(x) \iff -5.25 = \log_{10}(x) \iff 10^{-5.25} = x$.
You can use Wolfram or calculator to get approximate value $= 5.6234 \times 10^{-6}$.
taninamdar
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