I am trying to cancel out to reduce this:
$$\frac{ 6xh + 3h^2 + 5h }{ h }$$
Is it possible to cancel out the h's to become this; $$\frac{ 6x + 3 + 5 }{ h }$$
While the $3$ goes into the $6x$? So the final answer is $2x + 5$?
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4No. I'm not sure I can give more of an answer without knowing why you think you would be able to do that. – Callus - Reinstate Monica Mar 12 '14 at 02:34
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1After factoring $h$ out to get $\frac{h(6x+3h+5)}{h}$ (which is just the distributive property), you can cancel the common $h$ factor in the numerator and denominator to get $6x+3h+5$, which can't really be simplified any further. – Dustan Levenstein Mar 12 '14 at 02:35
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$\frac{6xh+3h^2+5h}{h}=\frac{h(6x+3h+5)}{h}=6x+5+3h$ – Eleven-Eleven Mar 12 '14 at 02:35
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You got a good idea, but it needs some cleaning up.
What you want to do is factor out the h. This will help you to cancel out the common $h$ in both the top and bottom of the problem. It would look like this,
$$\frac{ 6xh + 3h^2 + 5h }{ h }=\frac{ h(6x + 3h + 5) }{ h }$$
Assuming that $h\neq0$, we can cancel it out. Now you will get $6x+3h+5$ which can not be simplified further.
