What is $\alpha$ and $\beta$ ?
$$\frac{\alpha}{(\beta^2+1)^{3/2}}=12$$ $$\frac{\alpha}{(\beta^2+0.06^2)^{3/2}}=10$$
Thank you very much for your time.
What is $\alpha$ and $\beta$ ?
$$\frac{\alpha}{(\beta^2+1)^{3/2}}=12$$ $$\frac{\alpha}{(\beta^2+0.06^2)^{3/2}}=10$$
Thank you very much for your time.
There is no real root. If there were, $\alpha$ would have to be positive. And it is clear that for positive $\alpha$ and real $\beta$, the left-hand side of the second equation is greatr than the left-had side of the first.