Prove that $$\int_a^b f(x)\,dx = c\int_{a/c}^{b/c} f(cy)\,dy$$
I've tried to use subtitution rule, but I'm afraid I can't do this if f is not continuous.
Thanks.
Prove that $$\int_a^b f(x)\,dx = c\int_{a/c}^{b/c} f(cy)\,dy$$
I've tried to use subtitution rule, but I'm afraid I can't do this if f is not continuous.
Thanks.
Substituting $x=g\left(y\right)$ is allowed here under certain conditions on function $g$ (so not conditions on the integrand $f$). Here you do that with function $g\left(y\right)=cy$ which is okay if $c\neq0$.
Let $x=cy$. Therefore, $dx=c dy$, and the limits become the desired ones: $a/c$ and $b/c$. Therefore, the integral is:
$$\int_a^b f(x)\,dx = c\int_{a/c}^{b/c} f(cy)\,dy$$
Which is what we wanted.