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Prove that $$\int_a^b f(x)\,dx = c\int_{a/c}^{b/c} f(cy)\,dy$$

I've tried to use subtitution rule, but I'm afraid I can't do this if f is not continuous.

Thanks.

NasuSama
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2 Answers2

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Substituting $x=g\left(y\right)$ is allowed here under certain conditions on function $g$ (so not conditions on the integrand $f$). Here you do that with function $g\left(y\right)=cy$ which is okay if $c\neq0$.

drhab
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  • This really answers the question. The asker forgot to mention that $c \neq 0$, and you brought this up. Yes. This is certainly true. – NasuSama Mar 15 '14 at 14:45
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Let $x=cy$. Therefore, $dx=c dy$, and the limits become the desired ones: $a/c$ and $b/c$. Therefore, the integral is:

$$\int_a^b f(x)\,dx = c\int_{a/c}^{b/c} f(cy)\,dy$$

Which is what we wanted.