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It can be easily shown that a square may be cut in any number of (not necessarily same-sized) squares, except in 2, 3 or 5 squares. Are there any results regarding the same question for cubes? Is there a maximum number n without a cube-cutting solution?

Landei
  • 397

1 Answers1

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This seems to give an answer of $47$ with an argument to show why.

Mark Bennet
  • 100,194