The term radial vector does not seem to be usual in English (see the Wikipedia page on ellipses ), but it is in Spanish (see the same page in Spanish, look out for "radio vector" ). It is defined as "the line segment, in a hyperbola or ellipse, that joins a point with the focal points".
In the following plot, this line segment would amount to $ \overline{F_1 P} + \overline{F_2 P}$

As you can see, the point $P$ can be described with a simple pair of Cartesian coordinates $(x, y)$. If those coordinates really belong to an ellipse, then they should satisfy the relationship:
$$\tag{1} E = \left\{P \mid \overline{F_1 P} + \overline{F_2 P} = 2a\right\}$$
i.e. they are the set of all points $P$ such that the radial vector to both focal points $(F_{1}, F_{2})$ is a constant (namely, twice the semi-major radius $a$ of the ellipse).
The same relationship expressed in Cartesian coordinates gives the following:
$$\tag{2} \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$$
where $b$ is the semi-minor axis, which is related to $a$ through
$$\tag{3} e = \sqrt{a^2-b^2},$$
$$\tag{4} b = a \sqrt{1-e^2}$$
where $e$ is the ellipse eccentricity and may be another information you have on the ellipse.
If you do not know the axes $a$ and $b$ of the ellipse, or $a$ and $e$, pick two points from the ones you have in your data and plug them into the relationship $(2)$: now you have a set of two equations with two unknowns. Solve for $a$ and $b$, and check that the relationship holds with the same parameters for all other points.