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I am trying to get this equation $-x^2y'' - 2xy' + 2y = -4x^2$

into Piecewise Linear Rayleigh-Ritz format $-\frac{d}{dx} (p(x) \frac{dy}{dx}) + q(x)y = f(x)$

I pretty much needs to figure out what is $p(x), q(x), f(x)$

Thanks

Mary Star
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user1510863
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    Perhaps you should work out what $ - (p(x)y'(x))'+ q(x)y(x)$ becomes after expanding and compare it to the given expression. – Hans Engler Mar 30 '14 at 00:31
  • $$-x^2y'' - 2xy' + 2y = -4x^2 \Rightarrow -(x^2y''+2xy')+2y=-4x^2 \Rightarrow -(x^2y')'+2y=-4x^2$$ – Mary Star Mar 30 '14 at 00:31

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