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I need to know how I can prove this question. Prove that not every boolean function is equal to a boolean function constructed by only using And ($\wedge$) and Or ($\vee$)

Alt
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1 Answers1

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Consider a function $f$ where $f(\text{true}, \text{true}) = \text{false}$. Can you see how any function with this property can't be created with $\land$ and $\lor$?

DanielV
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