How is it possible that every imaginary number (multiple of i ) is also a complex number?
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1What's a complex number? – Apr 05 '14 at 13:51
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Every natural number is also a real number. The same concept. The imaginary numbers form a subset of the complex numbers. – drhab Apr 05 '14 at 13:52
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1$\mathbb{C}:={ a+bi|a,b\in\mathbb{R} }$ now choose $a=0$ – b00n heT Apr 05 '14 at 13:52
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Is it the root of some polynomial with real coefficients? Then it's a complex number. (One can further weaken that to only needing complex coefficients.) – Semiclassical Aug 02 '14 at 16:19
3 Answers
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Any real multiple of $ i $, say $ ai $, is also a complex number $0+ai $. Complex number is a number of the form $ a+bi$, where $ a, b\in \mathbb {R} $. Zero is obviously a real number, so everything works out nicely.
user132181
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First of all, lets see the definition of a complex number:
A complex number is a number that can be expressed in the form a + bi, where a and b are real numbers and i is the imaginary unit,
For an imaginaty number it is: 0+bi
Note that 0 is a real number, so it didn't break the rule.
Similarly any real number is: a+0i which is a complex number too.
Mohammad
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The standard definition of a complex number is any number that can be written as: $a+b\,i$ where $a,b\in\Bbb R$ and $i=\sqrt{-1}$. So even an imaginary number, that is a number of the form $b\,i$, is a complex number since it can be written as: $0+b\,i$.
Hakim
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