$\sum _{n=1}^{\infty \:}\left(\sqrt{n+\sqrt{n}}-\sqrt{n}\right)$ Can you show me the work for this question
Asked
Active
Viewed 71 times
0
-
can i see your attempt? Anything you tried or attempted? – Asimov Apr 06 '14 at 00:54
-
I wasn't sure where to start. I know it diverges by the nth term test but I wasn't sure how to show the work. The limit just confused me. – Lindsay Sinai Apr 06 '14 at 01:05
3 Answers
3
Multiply top and bottom by $\sqrt{n+\sqrt{n}}+\sqrt{n}$. You will see that the terms do not approach $0$, so the series diverges.
André Nicolas
- 507,029
1
$$ \sqrt{n+\sqrt{n}} -\sqrt{n}= \sqrt{n}\left[\sqrt{1+\frac 1{\sqrt{n}}}-1\right] \\ \sim \sqrt{n}\frac 1{2\sqrt{n}} = \frac 12 $$ hence the series is divergent, the partial sum being $\simeq \frac n2$
mookid
- 28,236
0
You could look at the integral of:
$$ \int \sqrt{x + \sqrt{x}} dx $$
or even multiply 1, expressed as:
$$ \sqrt{n + \sqrt{n}} + \sqrt{n} $$
and look where this series goes.
David Cardozo
- 635