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Could the fourth root of $1$ be $i$ (or $-i$)? I could show this by doing:

  1. $\sqrt[4]{1}$
  2. $\sqrt{\sqrt{1}}$
  3. $\sqrt{\pm{1}}$
  4. $\sqrt{1}$ OR $\sqrt{-1}$
  5. $\pm1$ OR $\pm i$
  6. $\{1, -1, i, -i\}$

Would you include the negative square root from step 3 and include $\pm i$? Or would you simply come up with $\pm1$?

Cookie
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2 Answers2

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Precisely, no. $i$ is a fourth root of $1$, and not the fourth root of $1$.

Ugo Iaba
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1's fourth roots are indeed {1, -1, i, -i}