All sides of a pentagon ABCDE are given. Angles A & C are given. Can such pentagon be created by straightedge and compass?
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you have enough information given to construct the triangles $ \triangle BAE $ and $ \triangle BCD $ (Side Angle Side given) so you can construct the segments EB and BD,
Then first construct the triangle $ \triangle DBE $ (all sides given) and then "add" the triangles $ \triangle BAE %$ and $ \triangle BCD $ to them.
good luck
Willemien
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A hint: consider the triangles $EAB$ and $BCD$.
Second hint: The side lengths $|EA|$ and $|AB|$ together with the angle at $A$ allow the construction of the triangle $EAB$; in particular, the length of the diagonal $|BE|$ is determined.
Christian Blatter
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Can you explain me the whole thing?? I am not getting it. – Satvik Mashkaria Apr 10 '14 at 09:52