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$$P(x)=\prod_{p\leq x}p$$

As you can see P(x) represents the product of primes which are not greater than x. Is there a asymptotic formula for this?

esege
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1 Answers1

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Note that if $\vartheta$ is the Chebyshev function, we have the relationship

\begin{align*} e^{\vartheta(x)} &= \operatorname{exp} \left(\sum_{p \le x} \log p\right) \\ &= \prod_{p \le x} p \end{align*}

So asymptotic bounds for the Chebyshev function carry over to the desired product.