What are the formula's to convert the following per hour intervals into meters per second (using meters/s from light speed):
The result should be decimal form of each interval with no E+/- in the float section.
**Note: Please edit tags as I couldn't find any relating to conversion or for formulas. I am actually surprised there were no other applicable tags aside from fractions as this is a basic mathematical principle.
Let's say you want to convert $5$ kilometers/hour to something in meters/s. $5$ km/hr is written as
$$\frac{5\ \text{km}}{1\ \text{hr}}$$
First we will get this km/hr to m/hr by using $1000$ m = $1$ km.
$$\frac{5\ \text{km}}{1\ \text{hr}}\times\frac{1000\ \text{m}}{1\ \text{km}}$$
This works because mutiplying by $1000$m/$1$km is the same as multiplying by $1$.
$$\require{cancel}\frac{5\ \cancel{\text{km}}}{1\ \text{hr}}\times\frac{1000\ \text{m}}{1\ \cancel{\text{km}}} = \frac{5000\ \text{m}}{1\ \text{hr}}$$
Now we go from m/hr to m/s using $1$hr = $60$min and $1$min = $60$s
$$\frac{5000\ \text{m}}{1\ \cancel{\text{hr}}}\times\frac{1\ \cancel{\text{hr}}}{60\ \cancel{\text{min}}}\times\frac{1\ \cancel{\text{min}}}{60\ \text{s}} = \frac{5000\ \text{m}}{60\times60\ \text{s}}$$ $$\begin{align}&=\frac{25}{18}\text{m/s}\\\\&\approx1.3889\text{m/s}\end{align}$$
(4^2)/((10^7) * 40)) – Kraang Prime Apr 14 '14 at 00:47m = km * 1000mps = (m / 3600)(mps = meteres per sec). Basically, i need to convert the measurement first, then divide the result by 3600 seconds formeters per second. (also, looking at the edit of your answer -- thats crazy ... do you have a program to assist with writing all that ? ) – Kraang Prime Apr 14 '14 at 01:09