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Suppose that $f \in C[-1,1]$ is an odd function on $[-1,1]$. Show that polynomial $p_n$ of least squares approximation for $f$ in the norm $|\cdot|$ is an odd function on $[-1,1]$.

user35603
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cambelot
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1 Answers1

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If the(!) least square approximation for $f(x)$ is $p_n(x)$, then the least square approximation for $-f(-x)$ is $-p_n(-x)$.