Determine if Jacobi method converges for any b for, $$\begin{bmatrix} 2 & 2\\ 3 & 4 \end{bmatrix}$$
The solution goes on like this...
D-(L+U) = $$\begin{bmatrix} 2 & 0\\ 0 & 4 \end{bmatrix} - \begin{bmatrix} 0 & -2\\ -3 & 0 \end{bmatrix}$$
D^{-1}(L+U) =$$\begin{bmatrix} 1/2 & 0\\ 0 & 1/4 \end{bmatrix}\begin{bmatrix} 0 & -2\\ -3 & 0 \end{bmatrix}= \begin{bmatrix} 0 & -1\\ -\frac{3}{4} & 0 \end{bmatrix}$$ After that we have, $$\begin{bmatrix} \lambda & 1\\ \frac{3}{4} & \lambda \end{bmatrix}$$
And, since $\lambda_{1} = -\sqrt\frac{3}{4}$ and $\lambda_{2} = \sqrt\frac{3}{4}$, $\rho(A)< 1$. This method converges.
Now I have a couple of questions on this...
Why do we have to take inverse when inverse is strictly prohibited in Numerical analysis? Can we use forward substitution instead?
How do you come up with$$\begin{bmatrix} \lambda & 1\\ \frac{3}{4} & \lambda \end{bmatrix}$$ from $$\begin{bmatrix} 0 & -1\\ -\frac{3}{4} & 0 \end{bmatrix}$$ and changed the sign? Can someone please explain me these? Thanks.