If I have $X_{1},\ldots,X_{n}$ a random sample from a Weibull distribution $X\sim WEI(\theta,2)$.How can I show that $Q=2\sum\limits_{i=1}^n X_{i}^2/\theta^2\sim \chi^2(2n)$.
I have not learnt any transformations for Weibull distributions. I believe that if it has a squared term is because it got to be standar normal somehow and then became a chi-squared. The pdf of Weibull is similar to the exponential one, but that did not help. I also try to use the Jacobian to make the transformation but that sum stopped me.