I believe that I have his correct but if someone could check it and see that'd be great. Here's a pic!
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1Seems good to me.. – Berci Apr 20 '14 at 20:25
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1If you're just looking to verify a solution, there's wolfram alpha for that. – David H Apr 20 '14 at 20:26
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Not a solution, a simplified version of an expression. – King Squirrel Apr 20 '14 at 20:27
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And thanks guys! – King Squirrel Apr 20 '14 at 20:27
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1In the 4th line, there’s a denominator of 4 in the first term. It seems to have disappeared in the next line. Also, it looks like $-4\cos^2(2x)$ accidentally became $-\color{red}{2}\cos^2(2x)$ between lines 7 and 8. I didn't look beyond that. – Steve Kass Apr 20 '14 at 20:36
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Yeah your right, I'll have to go over this one again, thanks a lot! – King Squirrel Apr 20 '14 at 20:38