1

We have $10$ numbered balls and $3$ boxes with capacities: $5$, $3$ and $2$ balls. With how many ways can we put the balls in the boxes? The boxes are distinguished.

I thought that it is like that:

$\binom{10}{5} \cdot \binom{5}{3} \cdot \binom{2}{2}$.Could you tell me if it is right?

evinda
  • 7,823

1 Answers1

3

Yes, indeed, your answer is correct.

amWhy
  • 209,954