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I thought this would be a common problem but googling hasn't helped.

If I have $\ln(ex)=\ln(y) $ what the next step to solve for $y$?

5xum
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2 Answers2

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If you notice that $y = e^{\ln y}$, then you have $y = e^{\ln (ex)}$ as well; but $e^{\ln(ex)} = ex$, so $y = ex$!

And if it is $\ln y = \ln (e^x)$, you can still say $y = e^{\ln y}$ so $y = e^{\ln (e^x)} = e^x$!

Hope this helps! Cheerio,

and as always,

Fiat Lux!!!

Robert Lewis
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  • Would there be a caution on the possible range of values if one is working in the real numbers as ln isn't defined for negative values? – JB King Apr 29 '14 at 08:40
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$$\ln a = \ln b\\ e^{\ln a} = e^{\ln b}\\ a = b$$

user137794
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