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I would like to understand how to find the first derivative with respect to $C_i$ of $$\mathcal{L}=\left[\int_{i=0}^1 C_i^{(\eta-1)/\eta}di\right]^{\eta/(\eta-1)} +\lambda\left[S-\int_{i=0}^1P_iC_idi\right]$$

The most difficult part here for me is that I can not figure out how I should treat those integrals. Could you please suggest me some readings or explain me (in an explicit way) how to derive the above expression?

Thank you in advance.

Charlie.

Charlie
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1 Answers1

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We can write the expression as $$ \mathcal{L}=\left[\int_{0}^1 [C(x)]^\zeta\,dx\right]^{1/\zeta} +\lambda\left[S-\int_{0}^1P(x)C(x)dx\right] $$ where $\zeta := (\eta-1)/\eta$. Then, $$ \frac{\partial \mathcal{L}}{\partial C} = \frac{1}{\zeta}\left[\int_{0}^1 C^\zeta\,dx\right]^{\frac{1-\zeta}{\zeta}}\,\frac{\partial}{\partial C}\left[\int_{0}^1 C^\zeta\,dx\right] - \lambda\,\frac{\partial}{\partial C}\left[\int_{0}^1PC\,dx\right] $$ The derivatives above can be interpreted in terms of the calculus of variations. For example, if $$ I[C] = \int_{0}^1 C(x)^\zeta\,dx $$ then $$ \frac{\delta I}{\delta C} = \frac{d}{dC}\left[C^\zeta\right] = \zeta C^{\zeta-1} $$ You will also find the following informative.