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In the year 2000, there are $p$ penguins. After $t$ years, the number of penguins is given by $$ 2500 \times 1.02^t$$ Calculate the number of penguins in the year $2000$.

I tried to substitute random values for $t$ to get a general pattern but I couldn't get an answer so please help.

Aspiring Mathlete
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    If this is is true for all integer numbers $ t $, then take $ t=0 $ to get the number of penguins in the year $2000 $. – DKal May 10 '14 at 18:04
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    Just remember that $x^0=1$ ! You will need to use this zillions of times in your life ! Cheers. – Claude Leibovici May 10 '14 at 18:48

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In that case, t=0, as there no years have passed since the year 2000. The answer is therefore 2500.

nickjamesuk
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