How would I show that the limit of
$$\lim_{n\rightarrow\infty}\sin\left(\frac{\pi(1+(-1)^nn)}{2(1+n)}\right)$$
doesn't exist.
Asked
Active
Viewed 56 times
1 Answers
0
Hint :
$$\sin\big(\frac{\pi(1+(-1)^{2n}2n)}{2(1+2n)}\big)=??$$
$$\sin\big(\frac{\pi(1+(-1)^{2n+1}(2n+1))}{2(1+(2n+1))}\big)=??$$
-
thanks i got the limits to be $1$ and $-1$, hence im assuming as theyre different the limit doesnt exist? – user148699 May 17 '14 at 16:41
-
yes... that is it... – May 17 '14 at 16:42