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I'm not quite sure how to go about simplifying this boolean expression, any help would be great.

X'Y'+X'Z'+Y'Z

Joe
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  • What do you mean by X' ? – Jika May 19 '14 at 20:11
  • Welcome to Math.SE. Could you please provide more information about the problem? Specifically, your notation. Also, it would be helpful to express any ideas you have about solving the problem. – homegrown May 19 '14 at 20:18
  • X' = NOT X. I know most of the laws and I can figure out most basic questions, however on this question all I can think of is to do the distribution law to get X'(Y'+Z')+YZ' but then i don't know what to do. – Joe May 19 '14 at 20:40

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You can reduce the three terms to two terms:

$$\begin{align} X'Y'+X'Z'+Y'Z &= X'Y'(Z + Z') + X'Z' + Y'Z \\ & = Z(X'Y' + Y') + Z'(X'Y'+X') \\ & = X'Z' + Y'Z \end{align}$$

Axel Kemper
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