How many different committees of 5 can be formed from 8 men and 7 women so as to include at least 2 women?
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Number of committees of $5$ where at least $2$ women are included
$$\sum_{x=2}^{5}{7 \choose x}\cdot{8 \choose 5-x}$$
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This might not be the answer OP needs, but it is the answer he deserves. – Arthur May 20 '14 at 10:30