$3y^2=x(1-x)^2$
By differentiation we can knwo that the sketch of this graph has one circle.
I want to draw a graph in maple. Implicit plot does not work well
So I will use parametric way.
Please give me a parametrization.
$3y^2=x(1-x)^2$
By differentiation we can knwo that the sketch of this graph has one circle.
I want to draw a graph in maple. Implicit plot does not work well
So I will use parametric way.
Please give me a parametrization.
Polynomial equations in two variables can be plotted like this
algcurves[plot_real_curve](3*y^2 - x*(1-x)^2, x, y);

You can improve the plots returned by implicitplot by including the gridrefine option:
plots:-implicitplot(3*y^2 = x*(1-x)^2, x= 0..2, y= -1..1, gridrefine= 3);
A parameterization of a polynomial curve can be obtained by
algcurves[parameterization](3*y^2 - x*(1-x)^2, x, y, t);
Maple responds:
[3*t^2/(t^2-2*t+1), -t*(-1+2*t+2*t^2)/(-3*t^2+3*t+t^3-1)]