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What is the contrapositive of this case:

If $f:X→Y$ is a continuous surjection bewteen separable compact metric spaces, where $X$ has dimension $n$ and $Y$ has dimension $m$, then there is a point $y∈Y$ whose preimage contains at least $n−m+1$ points.

DER
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1 Answers1

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The contrapositive of $A \rightarrow B$ is $\lnot B \rightarrow \lnot A$.

In your example, we have to "parse" the complex sentence according to the "if _, then ..." form.

We have that :

$A :=$ "$f : X \rightarrow Y$ is a continuous surjection bewteen separable compact metric spaces, where $X$ has dimension $n$ and $Y$ has dimension $m$"

and ;

$B :=$ "there is a point $y \in Y$ whose preimage contains at least $n−m+1$ points".

Thus, the contrapositve will be :

if not "there is a point $y \in Y$ whose preimage contains at least $n−m+1$ points, then not "$f : X \rightarrow Y$ is a continuous surjection bewteen separable compact metric spaces, where $X$ has dimension $n$ and $Y$ has dimension $m$"

or, in a slightly more palatable form :

if "not exists a point $y \in Y$ whose preimage contains at least $n−m+1$ points, then "$f : X \rightarrow Y$ is not a continuous surjection bewteen separable compact metric spaces, where $X$ has dimension $n$ and $Y$ has dimension $m$".