I was in doubt that we can solve these type of Equation or not: $\frac{\cos\theta}{\cos{\theta}^2}=k$ where $k$ is a given constant.
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1if you mean $\cos(\theta^2)$ on the denominator, then probably not, except for numerically. – Bennett Gardiner May 22 '14 at 10:09
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1Besides the special cases $k=0$, $k=\pm1$ and $k=\infty$, I doubt there exists a closed solution. – May 22 '14 at 10:11
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@BennettGardiner How could it be proven? – peterh May 22 '14 at 10:11
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This is typically an equation you cannot solve analytically. Only numerical methods would lead to a solution for the more general situation. In order to make life simpler, let us write $$f(\theta)=\cos(\theta)-k\cos(\theta^2)$$ A classical and simple method is Newton iterative scheme which starting with a guess $\theta_0$ will udpate according to $$\theta_{n+1}=\theta_{n}-\frac {f(\theta_n)} {f'(\theta_n)}$$ For illustration purposes, let us assume $k=10$ and search for the first positive solution for which we shall use $\theta_0=1$. The procedure will then provide the following iterates : $1.30415$, $1.24150$, $1.24030$ which is the solution.
Claude Leibovici
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