"Jack is on a bearing of 260 degrees from Jill. What is Jill's bearing from Jack?"
The answer is 080 degrees. I really can't figure out how. Any help is appreciated.
"Jack is on a bearing of 260 degrees from Jill. What is Jill's bearing from Jack?"
The answer is 080 degrees. I really can't figure out how. Any help is appreciated.
This looks more like a question in general relativity than trigonometry
If Jack is traveling on a bearing of $260^\circ$ relative to Jill then from Jacks perspective Jill is travelling in the exact opposite direction
Hence $260^\circ-180^\circ=080^\circ$
Consider the following diagram:

The rule about bearings is: "Point north and go clockwise".
The bearing of Jill from Jack $(\theta)$ and the angle $\gamma$ ($=260-180)$ are alternate angles, so they're equal.