$A,B$ and $C$ do not represent anything, if you consider each one of them separately. Note that you can multiply the equation $Ax+By+C=0$ for any nonzero number $k$ to get $kAx+kBy+kC=0,$ which has the same solutions and, so, define the same line.
What have a geometric interpretation are the quotients $-\frac{A}{B}$ and $-\frac{C}{B},$ assuming $B\ne 0.$ In such a case you have $y=-\frac{A}{B}x-\frac{C}{B}.$ Then $-\frac{A}{B}$ is the slope of the line and $-\frac{C}{B}$ is the $y$-coordinate of the point of intersection of the line with the $y$-axis. (That is, $\left(0,-\frac{B}{A}\right)$ is a point of the line.)
In case $B=0$ the line has equation $Ax+C=0,$ or $x=-\frac{C}{A}$ and it is a vertical line that intersects the $x$-axis at the point $\left(-\frac{C}{A},0\right).$