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If $\vert x\vert\leqslant a$ and $\vert y\vert\leqslant b$ can we create some inequality that contains $\vert\vert x\vert-\vert y\vert\vert$?

bibo_extreme
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2 Answers2

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You can write

$$ ||x|-|y|| \le \frac{|a+b|+|a-b|}{2} $$

0

For example: $\vert\vert x\vert-\vert y\vert\vert \leq max(a,b)$

Since we can assume that one variable is equal to 0 and the second one equals $max(a,b)$, there's nothing better that we can get.

Mitkel
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