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Given $T:\mathbb{R}^{2}\to \mathbb{R}$ s.t.

\begin{eqnarray*} |T(x)|\leq \sum_{k=1}^{2}|x_{k}|\,and\,|T(x)-T(y)|\leq \sum_{k=1}^{2}|x_{k}-y_{k}| \end{eqnarray*}

for all $x=(x_{1},x_{2}),\,y=(y_{1},y_{2})\in \mathbb{R}^{2}$

Assumption1: For all $i \in \{1,2\}$, $\lambda_{i}\geq0$.

Assumption2: For all $i,j \in \{1,2\}$, $a_{ij}\geq0$, $a_{ij}=a_{ji}$ and $\lambda_{j}\geq\sum_{i=1}^{2}a_{ij}$

We define $b_{ij}=\lambda_{i}\delta_{ij}-a_{ij}$ ($\delta_{ij}$ is Kronecker delta)

I want to show the following inequality:

\begin{eqnarray*} (\sum_{i,j=1}^{2}T(\alpha_{i1},\alpha_{i2})T(\alpha_{j1},\alpha_{j2})b_{ij})^{1/2}\leq\sum_{k=1}^{2}(\sum_{i,j=1}^{2}\alpha_{ki}\alpha_{kj}b_{ij})^{1/2} \end{eqnarray*}

Where $\alpha_{ij}\in \mathbb{R}$

(We may assume $\sum_{i,j=1}^{2}T(\alpha_{i1},\alpha_{i2})T(\alpha_{j1}\alpha_{j2})b_{ij} , \sum_{i,j=1}^{2}\alpha_{ki}\alpha_{kj}b_{ij}\geq0$)

My process:

Step1: Deduce the follwing identity

\begin{eqnarray*} \sum_{i,j=1}^{2}z_{i}z_{j}b_{ij}=\sum_{i<j}a_{ij}(z_{i}-z_{j})^{2}+\sum_{j=1}^{2}m_{j}z_{j}^{2} \end{eqnarray*}

$m_{j}=\lambda_{j}-\sum_{i=1}^{2}a_{ij}$($\geq 0$) by assumption1

From Step1 and assumption of $T$

\begin{eqnarray*} \sum_{i,j=1}^{2}T(\alpha_{i1},\alpha_{i2})T(\alpha_{j1},\alpha_{j2})b_{ij}&=&\sum_{i<j}a_{ij}\left|T(\alpha_{i1},\alpha_{i2})-T(\alpha_{j1},\alpha_{j2})\right|^{2}+\sum_{j=1}^{2}m_{j}\left|T(\alpha_{j1},\alpha_{j2})\right|^{2}\\ &\leq&\sum_{i<j}a_{ij}\left(\sum_{k=1}^{2}|\alpha_{ik}-\alpha_{jk}|\right)^{2}+\sum_{j=1}^{2}m_{j}\left(\sum_{k=1}^{2}|\alpha_{jk}|\right)^{2}\\ &=&\sum_{i<j}a_{ij}\left(\sum_{k=1}^{2}|\alpha_{ik}-\alpha_{jk}|\right)^{2}+\sum_{j=1}^{2}(\lambda_{j}-\sum_{i=1}^{2}a_{ij})\left(\sum_{k=1}^{2}|\alpha_{jk}|\right)^{2}\\ &=&\sum_{i<j}a_{ij}\left(\sum_{k=1}^{2}|\alpha_{ik}-\alpha_{jk}|\right)^{2}+\sum_{j=1}^{2}(\sum_{i=1}^{2}(\lambda_{j}\delta_{ij}-a_{ij}))\left(\sum_{k=1}^{2}|\alpha_{jk}|\right)^{2}\\ &=&\sum_{i<j}a_{ij}\left(\sum_{k=1}^{2}|\alpha_{ik}-\alpha_{jk}|\right)^{2}+\sum_{j=1}^{2}\sum_{i=1}^{2}b_{ij}\left(\sum_{k=1}^{2}|\alpha_{jk}|\right)^{2}\\ \end{eqnarray*}

How do I apply Minkowski's Inequality? Please tell me.

ko4
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